# $Id: jranke $ # Copyright (C) 2012 Johannes Ranke # Contact: jranke@uni-bremen.de # This file is part of the R package mkin # mkin is free software: you can redistribute it and/or modify it under the # terms of the GNU General Public License as published by the Free Software # Foundation, either version 3 of the License, or (at your option) any later # version. # This program is distributed in the hope that it will be useful, but WITHOUT # ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS # FOR A PARTICULAR PURPOSE. See the GNU General Public License for more # details. # You should have received a copy of the GNU General Public License along with # this program. If not, see # Check solution types for SFO {{{ test.SFO_solution_types <- function() { ot = seq(0, 100, by = 1) SFO <- mkinmod(parent = list(type = "SFO")) SFO.analytical <- round(subset(mkinpredict(SFO, c(k_parent_sink = 0.1), c(parent = 100), ot, solution_type = "analytical"), time == 100), digits=5) SFO.deSolve <- round(subset(mkinpredict(SFO, c(k_parent_sink = 0.1), c(parent = 100), ot, solution_type = "deSolve"), time == 100), digits=5) SFO.eigen <- round(subset(mkinpredict(SFO, c(k_parent_sink = 0.1), c(parent = 100), ot, solution_type = "eigen"), time == 100), digits=5) checkEquals(SFO.analytical, SFO.deSolve) checkEquals(SFO.analytical, SFO.eigen) } # }}} # Check solution types for FOMC {{{ test.FOMC_solution_types <- function() { ot = seq(0, 100, by = 1) FOMC <- mkinmod(parent = list(type = "FOMC")) FOMC.analytical <- round(subset(mkinpredict(FOMC, c(alpha = 1, beta = 10), c(parent = 100), ot, solution_type = "analytical"), time == 100), digits=5) FOMC.deSolve <- round(subset(mkinpredict(FOMC, c(alpha = 1, beta = 10), c(parent = 100), ot, solution_type = "deSolve"), use_compiled = FALSE, time == 100), digits=5) checkEquals(FOMC.analytical, FOMC.deSolve) if (require(ccSolve)) { checkTrue(!is.null(FOMC$compiled)) FOMC.deSolve.compiled <- round(subset(mkinpredict(FOMC, c(alpha = 1, beta = 10), c(parent = 100), ot, solution_type = "deSolve"), time == 100), digits=5) checkEquals(FOMC.analytical, FOMC.deSolve.compiled) } } # }}} # Check model specification and solution types for SFO_SFO {{{ # Relative Tolerance is 0.01% # Do not use time 0, as eigenvalue based solution does not give 0 at time 0 for metabolites # and relative tolerance is thus not met test.SFO_solution_types <- function() { tol = 0.01 SFO_SFO.1 <- mkinmod(parent = list(type = "SFO", to = "m1"), m1 = list(type = "SFO"), use_of_ff = "min") SFO_SFO.2 <- mkinmod(parent = list(type = "SFO", to = "m1"), m1 = list(type = "SFO"), use_of_ff = "max") ot = seq(0, 100, by = 1) r.1.e <- subset(mkinpredict(SFO_SFO.1, c(k_parent_m1 = 0.1, k_parent_sink = 0.1, k_m1_sink = 0.1), c(parent = 100, m1 = 0), ot, solution_type = "eigen"), time %in% c(1, 10, 50, 100)) r.1.d <- subset(mkinpredict(SFO_SFO.1, c(k_parent_m1 = 0.1, k_parent_sink = 0.1, k_m1_sink = 0.1), c(parent = 100, m1 = 0), ot, solution_type = "deSolve"), time %in% c(1, 10, 50, 100)) r.2.e <- subset(mkinpredict(SFO_SFO.2, c(k_parent = 0.2, f_parent_to_m1 = 0.5, k_m1 = 0.1), c(parent = 100, m1 = 0), ot, solution_type = "eigen"), time %in% c(1, 10, 50, 100)) r.2.d <- subset(mkinpredict(SFO_SFO.2, c(k_parent = 0.2, f_parent_to_m1 = 0.5, k_m1 = 0.1), c(parent = 100, m1 = 0), ot, solution_type = "deSolve"), time %in% c(1, 10, 50, 100)) # Compare eigen and deSolve for minimum use of formation fractions dev.1.e_d.percent = 100 * (r.1.e[-1] - r.1.d[-1])/r.1.e[-1] dev.1.e_d.percent = as.numeric(unlist((dev.1.e_d.percent))) dev.1.e_d.percent = ifelse(is.na(dev.1.e_d.percent), 0, dev.1.e_d.percent) checkIdentical(dev.1.e_d.percent < tol, rep(TRUE, length(dev.1.e_d.percent))) # Compare eigen and deSolve for maximum use of formation fractions dev.2.e_d.percent = 100 * (r.2.e[-1] - r.2.d[-1])/r.2.e[-1] dev.2.e_d.percent = as.numeric(unlist((dev.2.e_d.percent))) dev.2.e_d.percent = ifelse(is.na(dev.2.e_d.percent), 0, dev.2.e_d.percent) checkIdentical(dev.2.e_d.percent < tol, rep(TRUE, length(dev.2.e_d.percent))) # Compare minimum and maximum use of formation fractions dev.1_2.e.percent = 100 * (r.1.e[-1] - r.2.e[-1])/r.1.e[-1] dev.1_2.e.percent = as.numeric(unlist((dev.1_2.e.percent))) dev.1_2.e.percent = ifelse(is.na(dev.1_2.e.percent), 0, dev.1_2.e.percent) checkIdentical(dev.1_2.e.percent < tol, rep(TRUE, length(dev.1_2.e.percent))) } # }}} # vim: set foldmethod=marker ts=2 sw=2 expandtab: