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<h1> Single First-Order Reversible Binding kinetics </h1>
<div class="row">
<div class="span8">
<h2>Usage</h2>
<pre><span class="functioncall"><a href='SFORB.solution.html'>SFORB.solution</a></span><span class="keyword">(</span><span class="symbol">t</span><span class="keyword">,</span> <span class="symbol">parent.0</span><span class="keyword">,</span> <span class="symbol">k_12</span><span class="keyword">,</span> <span class="symbol">k_21</span><span class="keyword">,</span> <span class="symbol">k_1output</span><span class="keyword">)</span></pre>
<h2>Arguments</h2>
<dl>
<dt>t</dt>
<dd> Time. </dd>
<dt>parent.0</dt>
<dd> Starting value for the response variable at time zero. </dd>
<dt>k_12</dt>
<dd> Kinetic constant describing transfer from free to bound. </dd>
<dt>k_21</dt>
<dd> Kinetic constant describing transfer from bound to free. </dd>
<dt>k_1output</dt>
<dd> Kinetic constant describing degradation of the free fraction. </dd>
</dl>
<div class="Description">
<h2>Description</h2>
<p>Function describing the solution of the differential equations describing
the kinetic model with first-order terms for a two-way transfer from a free
to a bound fraction, and a first-order degradation term for the free
fraction. The initial condition is a defined amount in the free fraction and
no substance in the bound fraction.</p>
</div>
<div class="Value">
<h2>Value</h2>
<p><dl>
The value of the response variable, which is the sum of free and bound
fractions at time <code>t</code>.
</dl></p>
</div>
<div class="References">
<h2>References</h2>
<p>FOCUS (2006) “Guidance Document on Estimating Persistence and
Degradation Kinetics from Environmental Fate Studies on Pesticides in EU
Registration” Report of the FOCUS Work Group on Degradation Kinetics,
EC Document Reference Sanco/10058/2005 version 2.0, 434 pp,
<a href = 'http://focus.jrc.ec.europa.eu/dk'>http://focus.jrc.ec.europa.eu/dk</a></p>
</div>
<h2 id="examples">Examples</h2>
<pre class="examples"><div class='input'> <span class="comment">## Not run: plot(function(x) SFORB.solution(x, 100, 0.5, 2, 3), 0, 2)</span></div></pre>
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