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# Calculate a time course of relative concentrations based on an mkinmod model
Calculate a time course of relative concentrations based on an mkinmod
model
## Usage
``` r
pfm_degradation(
model = "SFO",
DT50 = 1000,
parms = c(k_parent = log(2)/DT50),
years = 1,
step_days = 1,
times = seq(0, years * 365, by = step_days)
)
```
## Arguments
- model:
The degradation model to be used. Either a parent only model like
'SFO' or 'FOMC', or an mkinmod object
- DT50:
The half-life. This is only used when simple exponential decline is
calculated (SFO model).
- parms:
The parameters used for the degradation model
- years:
For how many years should the degradation be predicted?
- step_days:
What step size in days should the output have?
- times:
The output times
## Value
A data frame containing the output times and the concentrations assuming
initial concentrations of 1 for the parent and zero for metabolites, if
any.
## Author
Johannes Ranke
## Examples
``` r
# Simple example of an SFO decline curve
sfo_out <- pfm_degradation("SFO", DT50 = 10)
head(sfo_out)
#> time parent
#> 0 0 1.0000000
#> 1 1 0.9330330
#> 2 2 0.8705506
#> 3 3 0.8122524
#> 4 4 0.7578583
#> 5 5 0.7071068
# Fictive example with a metabolite where we first generate an SFO-SFO model
sfo_sfo <- mkinmod(
parent = mkinsub("SFO", to = "metabolite"),
metabolite = mkinsub("SFO"))
#> Temporary DLL for differentials generated and loaded
sfo_sfo_out <- pfm_degradation(sfo_sfo,
parms = c(k_parent = 0.1, f_parent_to_metabolite = 0.5, k_metabolite = 0.02))
plot(
sfo_sfo_out[, "time"],
sfo_sfo_out[, "parent"], type = "l",
xlab = "Time", ylab = "Relative concentration",
xlim = c(0, 100))
lines(
sfo_sfo_out[, "time"],
sfo_sfo_out[, "metabolite"], lty = 2)
```
|
